Base | Representation |
---|---|
bin | 11101010001101… |
… | …011000011001111 |
3 | 1021020020010101022 |
4 | 131101223003033 |
5 | 2001220001142 |
6 | 120423304355 |
7 | 15112615322 |
oct | 3521530317 |
9 | 1236203338 |
10 | 491172047 |
11 | 232287913 |
12 | 1185ab0bb |
13 | 7a9b3b62 |
14 | 493387b9 |
15 | 2d1c26d2 |
hex | 1d46b0cf |
491172047 has 2 divisors, whose sum is σ = 491172048. Its totient is φ = 491172046.
The previous prime is 491172037. The next prime is 491172127. The reversal of 491172047 is 740271194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 491172047 - 212 = 491167951 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 491171998 and 491172016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (491172037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245586023 + 245586024.
It is an arithmetic number, because the mean of its divisors is an integer number (245586024).
Almost surely, 2491172047 is an apocalyptic number.
491172047 is a deficient number, since it is larger than the sum of its proper divisors (1).
491172047 is an equidigital number, since it uses as much as digits as its factorization.
491172047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14112, while the sum is 35.
The square root of 491172047 is about 22162.4016523481. The cubic root of 491172047 is about 789.0015945882.
The spelling of 491172047 in words is "four hundred ninety-one million, one hundred seventy-two thousand, forty-seven".
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