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49125497 is a prime number
BaseRepresentation
bin1011101101100…
…1100001111001
310102102211111212
42323121201321
5100034003442
64512532505
71134363011
oct273314171
9112384455
1049125497
1125803793
1214551135
13a240355
14674ac41
1544a5a82
hex2ed9879

49125497 has 2 divisors, whose sum is σ = 49125498. Its totient is φ = 49125496.

The previous prime is 49125473. The next prime is 49125499. The reversal of 49125497 is 79452194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29800681 + 19324816 = 5459^2 + 4396^2 .

It is a cyclic number.

It is not a de Polignac number, because 49125497 - 216 = 49059961 is a prime.

It is a super-4 number, since 4×491254974 (a number of 32 digits) contains 4444 as substring.

Together with 49125499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (49125499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24562748 + 24562749.

It is an arithmetic number, because the mean of its divisors is an integer number (24562749).

Almost surely, 249125497 is an apocalyptic number.

It is an amenable number.

49125497 is a deficient number, since it is larger than the sum of its proper divisors (1).

49125497 is an equidigital number, since it uses as much as digits as its factorization.

49125497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 41.

The square root of 49125497 is about 7008.9583391543. The cubic root of 49125497 is about 366.2427073218.

The spelling of 49125497 in words is "forty-nine million, one hundred twenty-five thousand, four hundred ninety-seven".