4913000000 has 196 divisors, whose sum is σ = 12947881140. Its totient is φ = 1849600000.

The previous prime is 4912999981. The next prime is 4913000023. The reversal of 4913000000 is 3194.

The cubic root of 4913000000 is 1700.

It is a perfect power (a cube), and thus also a powerful number.

It can be written as a sum of positive squares in 14 ways, for example, as 4253126656 + 659873344 = 65216^2 + 25688^2 .

It is a Harshad number since it is a multiple of its sum of digits (17).

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 288999992 + ... + 289000008.

Almost surely, 2^4913000000 is an apocalyptic number.

4913000000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4913000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6473940570).

4913000000 is an abundant number, since it is smaller than the sum of its proper divisors (8034881140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4913000000 is an frugal number, since it uses more digits than its factorization.

4913000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93 (or 24 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 4913000000 is about 70092.7956355002.

Multiplying 4913000000 by its sum of digits (17), we get a square (83521000000 = 289000²).

4913000000 divided by its sum of digits (17) gives a square (289000000 = 17000²).

Adding to 4913000000 its reverse (3194), we get a palindrome (4913003194).

The spelling of 4913000000 in words is "four billion, nine hundred thirteen million", and thus it is an aban number.