Base | Representation |
---|---|
bin | 10110010110000100010111… |
… | …11101010010001101001111 |
3 | 20102222102121021002010211021 |
4 | 23023002023331102031033 |
5 | 22420024103113331443 |
6 | 252301042231335011 |
7 | 13231005031244332 |
oct | 1313021375221517 |
9 | 212872537063737 |
10 | 49136773964623 |
11 | 14724874a011a4 |
12 | 5617052221467 |
13 | 2155768863367 |
14 | c1c338188619 |
15 | 5a3260cc79ed |
hex | 2cb08bf5234f |
49136773964623 has 2 divisors, whose sum is σ = 49136773964624. Its totient is φ = 49136773964622.
The previous prime is 49136773964617. The next prime is 49136773964633. The reversal of 49136773964623 is 32646937763194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49136773964623 - 25 = 49136773964591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49136773964633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24568386982311 + 24568386982312.
It is an arithmetic number, because the mean of its divisors is an integer number (24568386982312).
Almost surely, 249136773964623 is an apocalyptic number.
49136773964623 is a deficient number, since it is larger than the sum of its proper divisors (1).
49136773964623 is an equidigital number, since it uses as much as digits as its factorization.
49136773964623 is an evil number, because the sum of its binary digits is even.
The product of its digits is 740710656, while the sum is 70.
The spelling of 49136773964623 in words is "forty-nine trillion, one hundred thirty-six billion, seven hundred seventy-three million, nine hundred sixty-four thousand, six hundred twenty-three".
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