49137992513280 has 1296 divisors, whose sum is σ = 205196623343712. Its totient is φ = 11211374592000.

The previous prime is 49137992513273. The next prime is 49137992513287. The reversal of 49137992513280 is 8231529973194.

49137992513280 is a `hidden beast` number, since 4 + 9 + 1 + 3 + 7 + 9 + 92 + 513 + 28 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (49137992513273) and next prime (49137992513287).

It is a tau number, because it is divible by the number of its divisors (1296).

It is a super-2 number, since 2×49137992513280² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (49137992513287) by changing a digit.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 639770880 + ... + 639847680.

Almost surely, 2^{49137992513280} is an apocalyptic number.

49137992513280 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49137992513280, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (102598311671856).

49137992513280 is an abundant number, since it is smaller than the sum of its proper divisors (156058630830432).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49137992513280 is a wasteful number, since it uses less digits than its factorization.

49137992513280 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76876 (or 76839 counting only the distinct ones).

The product of its (nonzero) digits is 29393280, while the sum is 63.

The spelling of 49137992513280 in words is "forty-nine trillion, one hundred thirty-seven billion, nine hundred ninety-two million, five hundred thirteen thousand, two hundred eighty".