Base | Representation |
---|---|
bin | 101101110001001100… |
… | …101000101000001000 |
3 | 11200211220200120120112 |
4 | 231301030220220020 |
5 | 1301121301342200 |
6 | 34324253413452 |
7 | 3356554135055 |
oct | 556114505010 |
9 | 150756616515 |
10 | 49143777800 |
11 | 199294216a7 |
12 | 963619a288 |
13 | 4832563580 |
14 | 2542b2c02c |
15 | 1429614535 |
hex | b71328a08 |
49143777800 has 48 divisors (see below), whose sum is σ = 123048465540. Its totient is φ = 18145393920.
The previous prime is 49143777763. The next prime is 49143777811. The reversal of 49143777800 is 877734194.
It can be written as a sum of positive squares in 6 ways, for example, as 1386668644 + 47757109156 = 37238^2 + 218534^2 .
It is a super-2 number, since 2×491437778002 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (50).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9448127 + ... + 9453326.
Almost surely, 249143777800 is an apocalyptic number.
49143777800 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
49143777800 is an abundant number, since it is smaller than the sum of its proper divisors (73904687740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
49143777800 is a wasteful number, since it uses less digits than its factorization.
49143777800 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18901482 (or 18901473 counting only the distinct ones).
The product of its (nonzero) digits is 1185408, while the sum is 50.
The spelling of 49143777800 in words is "forty-nine billion, one hundred forty-three million, seven hundred seventy-seven thousand, eight hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •