Base | Representation |
---|---|
bin | 10110010110010011100010… |
… | …01000110101001011100011 |
3 | 20110000012121112212210111221 |
4 | 23023021301020311023203 |
5 | 22420142240432104334 |
6 | 252304510051315511 |
7 | 13231413532016455 |
oct | 1313116110651343 |
9 | 213005545783457 |
10 | 49144913941219 |
11 | 14728271795088 |
12 | 56187442abb97 |
13 | 21564650a5c65 |
14 | c1c8ab28c2d5 |
15 | 5a358a7228b4 |
hex | 2cb2712352e3 |
49144913941219 has 2 divisors, whose sum is σ = 49144913941220. Its totient is φ = 49144913941218.
The previous prime is 49144913941217. The next prime is 49144913941309. The reversal of 49144913941219 is 91214931944194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49144913941219 - 21 = 49144913941217 is a prime.
It is a super-2 number, since 2×491449139412192 (a number of 28 digits) contains 22 as substring.
Together with 49144913941217, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (49144913941217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24572456970609 + 24572456970610.
It is an arithmetic number, because the mean of its divisors is an integer number (24572456970610).
Almost surely, 249144913941219 is an apocalyptic number.
49144913941219 is a deficient number, since it is larger than the sum of its proper divisors (1).
49144913941219 is an equidigital number, since it uses as much as digits as its factorization.
49144913941219 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10077696, while the sum is 61.
The spelling of 49144913941219 in words is "forty-nine trillion, one hundred forty-four billion, nine hundred thirteen million, nine hundred forty-one thousand, two hundred nineteen".
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