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49149791497 is a prime number
BaseRepresentation
bin101101110001100011…
…100100110100001001
311200212100000002211001
4231301203210310021
51301124321311442
634325030335001
73356656222522
oct556143446411
9150770002731
1049149791497
11199318598a4
1296381ba461
13483388a881
142543855849
151429e012b7
hexb718e4d09

49149791497 has 2 divisors, whose sum is σ = 49149791498. Its totient is φ = 49149791496.

The previous prime is 49149791479. The next prime is 49149791503. The reversal of 49149791497 is 79419794194.

Together with previous prime (49149791479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49133598921 + 16192576 = 221661^2 + 4024^2 .

It is a cyclic number.

It is not a de Polignac number, because 49149791497 - 215 = 49149758729 is a prime.

It is not a weakly prime, because it can be changed into another prime (49149791437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24574895748 + 24574895749.

It is an arithmetic number, because the mean of its divisors is an integer number (24574895749).

Almost surely, 249149791497 is an apocalyptic number.

It is an amenable number.

49149791497 is a deficient number, since it is larger than the sum of its proper divisors (1).

49149791497 is an equidigital number, since it uses as much as digits as its factorization.

49149791497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20575296, while the sum is 64.

The spelling of 49149791497 in words is "forty-nine billion, one hundred forty-nine million, seven hundred ninety-one thousand, four hundred ninety-seven".