Base | Representation |
---|---|
bin | 10110010110011110111111… |
… | …10111011111011000011111 |
3 | 20110000210111100020221222102 |
4 | 23023033133313133120133 |
5 | 22420242341024240014 |
6 | 252311404401035315 |
7 | 13232022152030546 |
oct | 1313173767373037 |
9 | 213023440227872 |
10 | 49151066633759 |
11 | 1472a939827052 |
12 | 5619980925b3b |
13 | 2156c059a432c |
14 | c1ccd248715d |
15 | 5a37ea96c8de |
hex | 2cb3dfddf61f |
49151066633759 has 2 divisors, whose sum is σ = 49151066633760. Its totient is φ = 49151066633758.
The previous prime is 49151066633639. The next prime is 49151066633791. The reversal of 49151066633759 is 95733666015194.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49151066633759 - 232 = 49146771666463 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 49151066633695 and 49151066633704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49151062633759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24575533316879 + 24575533316880.
It is an arithmetic number, because the mean of its divisors is an integer number (24575533316880).
Almost surely, 249151066633759 is an apocalyptic number.
49151066633759 is a deficient number, since it is larger than the sum of its proper divisors (1).
49151066633759 is an equidigital number, since it uses as much as digits as its factorization.
49151066633759 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110224800, while the sum is 65.
The spelling of 49151066633759 in words is "forty-nine trillion, one hundred fifty-one billion, sixty-six million, six hundred thirty-three thousand, seven hundred fifty-nine".
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