Base | Representation |
---|---|
bin | 101101110001101100… |
… | …010111101101101101 |
3 | 11200212111100020112222 |
4 | 231301230113231231 |
5 | 1301130414102013 |
6 | 34325152005125 |
7 | 3360014634506 |
oct | 556154275555 |
9 | 150774306488 |
10 | 49152097133 |
11 | 19933094087 |
12 | 9638b307a5 |
13 | 48341b7159 |
14 | 2543c95bad |
15 | 142a209508 |
hex | b71b17b6d |
49152097133 has 2 divisors, whose sum is σ = 49152097134. Its totient is φ = 49152097132.
The previous prime is 49152097121. The next prime is 49152097207. The reversal of 49152097133 is 33179025194.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37759096489 + 11393000644 = 194317^2 + 106738^2 .
It is a cyclic number.
It is not a de Polignac number, because 49152097133 - 222 = 49147902829 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49151097133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24576048566 + 24576048567.
It is an arithmetic number, because the mean of its divisors is an integer number (24576048567).
Almost surely, 249152097133 is an apocalyptic number.
It is an amenable number.
49152097133 is a deficient number, since it is larger than the sum of its proper divisors (1).
49152097133 is an equidigital number, since it uses as much as digits as its factorization.
49152097133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 204120, while the sum is 44.
The spelling of 49152097133 in words is "forty-nine billion, one hundred fifty-two million, ninety-seven thousand, one hundred thirty-three".
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