Base | Representation |
---|---|
bin | 1011101110010… |
… | …1110111101001 |
3 | 10102112101211212 |
4 | 2323211313221 |
5 | 100042113131 |
6 | 4514002505 |
7 | 1134663245 |
oct | 273456751 |
9 | 112471755 |
10 | 49176041 |
11 | 25838762 |
12 | 14576435 |
13 | a25a365 |
14 | 6761425 |
15 | 44b5a2b |
hex | 2ee5de9 |
49176041 has 2 divisors, whose sum is σ = 49176042. Its totient is φ = 49176040.
The previous prime is 49176031. The next prime is 49176059. The reversal of 49176041 is 14067194.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48930025 + 246016 = 6995^2 + 496^2 .
It is a cyclic number.
It is not a de Polignac number, because 49176041 - 210 = 49175017 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 49175989 and 49176007.
It is not a weakly prime, because it can be changed into another prime (49176031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24588020 + 24588021.
It is an arithmetic number, because the mean of its divisors is an integer number (24588021).
Almost surely, 249176041 is an apocalyptic number.
It is an amenable number.
49176041 is a deficient number, since it is larger than the sum of its proper divisors (1).
49176041 is an equidigital number, since it uses as much as digits as its factorization.
49176041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 32.
The square root of 49176041 is about 7012.5630834952. The cubic root of 49176041 is about 366.3682702679.
The spelling of 49176041 in words is "forty-nine million, one hundred seventy-six thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •