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491778194987557 is a prime number
BaseRepresentation
bin110111111010001010000100…
…0100111101101101000100101
32101111020112110221221011020101
41233310110020213231220211
51003424243220404100212
64501531441154304101
7205404542055432442
oct15764241047555045
92344215427834211
10491778194987557
11132771a634918a5
12471a5aaa588031
131815363c14c34a
148962297bd49c9
153bcc42d09e157
hex1bf45089eda25

491778194987557 has 2 divisors, whose sum is σ = 491778194987558. Its totient is φ = 491778194987556.

The previous prime is 491778194987507. The next prime is 491778194987587. The reversal of 491778194987557 is 755789491877194.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 409275598374721 + 82502596612836 = 20230561^2 + 9083094^2 .

It is a cyclic number.

It is not a de Polignac number, because 491778194987557 - 247 = 351040706632229 is a prime.

It is a super-3 number, since 3×4917781949875573 (a number of 45 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (491778194987507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 245889097493778 + 245889097493779.

It is an arithmetic number, because the mean of its divisors is an integer number (245889097493779).

Almost surely, 2491778194987557 is an apocalyptic number.

It is an amenable number.

491778194987557 is a deficient number, since it is larger than the sum of its proper divisors (1).

491778194987557 is an equidigital number, since it uses as much as digits as its factorization.

491778194987557 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 44808422400, while the sum is 91.

The spelling of 491778194987557 in words is "four hundred ninety-one trillion, seven hundred seventy-eight billion, one hundred ninety-four million, nine hundred eighty-seven thousand, five hundred fifty-seven".