Base | Representation |
---|---|
bin | 101101110100000000… |
… | …110010110010110011 |
3 | 11200222012112222121112 |
4 | 231310000302302303 |
5 | 1301220344132423 |
6 | 34333101543535 |
7 | 3360666434543 |
oct | 556400626263 |
9 | 150865488545 |
10 | 49191005363 |
11 | 19953049445 |
12 | 9649b74bab |
13 | 483c28aa86 |
14 | 2549103323 |
15 | 142d842a78 |
hex | b74032cb3 |
49191005363 has 2 divisors, whose sum is σ = 49191005364. Its totient is φ = 49191005362.
The previous prime is 49191005359. The next prime is 49191005371. The reversal of 49191005363 is 36350019194.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49191005363 - 22 = 49191005359 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49191005363.
It is not a weakly prime, because it can be changed into another prime (49191005323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24595502681 + 24595502682.
It is an arithmetic number, because the mean of its divisors is an integer number (24595502682).
Almost surely, 249191005363 is an apocalyptic number.
49191005363 is a deficient number, since it is larger than the sum of its proper divisors (1).
49191005363 is an equidigital number, since it uses as much as digits as its factorization.
49191005363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 87480, while the sum is 41.
The spelling of 49191005363 in words is "forty-nine billion, one hundred ninety-one million, five thousand, three hundred sixty-three".
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