Base | Representation |
---|---|
bin | 101101110100000000… |
… | …110010110010111011 |
3 | 11200222012112222121211 |
4 | 231310000302302323 |
5 | 1301220344132441 |
6 | 34333101543551 |
7 | 3360666434554 |
oct | 556400626273 |
9 | 150865488554 |
10 | 49191005371 |
11 | 19953049452 |
12 | 9649b74bb7 |
13 | 483c28aa91 |
14 | 254910332b |
15 | 142d842a81 |
hex | b74032cbb |
49191005371 has 2 divisors, whose sum is σ = 49191005372. Its totient is φ = 49191005370.
The previous prime is 49191005363. The next prime is 49191005387. The reversal of 49191005371 is 17350019194.
49191005371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49191005371 - 23 = 49191005363 is a prime.
It is not a weakly prime, because it can be changed into another prime (49191005471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24595502685 + 24595502686.
It is an arithmetic number, because the mean of its divisors is an integer number (24595502686).
Almost surely, 249191005371 is an apocalyptic number.
49191005371 is a deficient number, since it is larger than the sum of its proper divisors (1).
49191005371 is an equidigital number, since it uses as much as digits as its factorization.
49191005371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34020, while the sum is 40.
The spelling of 49191005371 in words is "forty-nine billion, one hundred ninety-one million, five thousand, three hundred seventy-one".
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