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4920544001 is a prime number
BaseRepresentation
bin1001001010100100…
…11000101100000001
3110200220212112102102
410211102120230001
540034124402001
62132132200145
7232635635222
oct44522305401
913626775372
104920544001
1120a557859a
12b53a69055
1360555bcc9
143496db249
151dbeade6b
hex125498b01

4920544001 has 2 divisors, whose sum is σ = 4920544002. Its totient is φ = 4920544000.

The previous prime is 4920543989. The next prime is 4920544003. The reversal of 4920544001 is 1004450294.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3831610000 + 1088934001 = 61900^2 + 32999^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4920544001 is a prime.

Together with 4920544003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4920544003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2460272000 + 2460272001.

It is an arithmetic number, because the mean of its divisors is an integer number (2460272001).

Almost surely, 24920544001 is an apocalyptic number.

It is an amenable number.

4920544001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4920544001 is an equidigital number, since it uses as much as digits as its factorization.

4920544001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

The square root of 4920544001 is about 70146.5893753930. The cubic root of 4920544001 is about 1700.8696820039.

Adding to 4920544001 its reverse (1004450294), we get a palindrome (5924994295).

The spelling of 4920544001 in words is "four billion, nine hundred twenty million, five hundred forty-four thousand, one".