Search a number
-
+
49211824403983 is a prime number
BaseRepresentation
bin10110011000010000001010…
…10011111111011000001111
320110020121022122201111001111
423030020011103333120033
522422241304021411413
6252355333334552451
713236302612406103
oct1314100523773017
9213217278644044
1049211824403983
1114753687a2109a
1256296b8508727
13215c869419967
14c21c17831903
155a51a49a4d3d
hex2cc2054ff60f

49211824403983 has 2 divisors, whose sum is σ = 49211824403984. Its totient is φ = 49211824403982.

The previous prime is 49211824403971. The next prime is 49211824404019. The reversal of 49211824403983 is 38930442811294.

49211824403983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 49211824403983 - 29 = 49211824403471 is a prime.

It is a super-2 number, since 2×492118244039832 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49211824409983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24605912201991 + 24605912201992.

It is an arithmetic number, because the mean of its divisors is an integer number (24605912201992).

Almost surely, 249211824403983 is an apocalyptic number.

49211824403983 is a deficient number, since it is larger than the sum of its proper divisors (1).

49211824403983 is an equidigital number, since it uses as much as digits as its factorization.

49211824403983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11943936, while the sum is 58.

The spelling of 49211824403983 in words is "forty-nine trillion, two hundred eleven billion, eight hundred twenty-four million, four hundred three thousand, nine hundred eighty-three".