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492135433 is a prime number
BaseRepresentation
bin11101010101010…
…110010000001001
31021022001001220021
4131111112100021
52001441313213
6120500100441
715124040116
oct3525262011
91238031807
10492135433
112328856a9
12118994721
137ac604ca
144950990d
152d312d8d
hex1d556409

492135433 has 2 divisors, whose sum is σ = 492135434. Its totient is φ = 492135432.

The previous prime is 492135421. The next prime is 492135443. The reversal of 492135433 is 334531294.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 365077449 + 127057984 = 19107^2 + 11272^2 .

It is a cyclic number.

It is not a de Polignac number, because 492135433 - 25 = 492135401 is a prime.

It is equal to p25963009 and since 492135433 and 25963009 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (492135443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246067716 + 246067717.

It is an arithmetic number, because the mean of its divisors is an integer number (246067717).

Almost surely, 2492135433 is an apocalyptic number.

It is an amenable number.

492135433 is a deficient number, since it is larger than the sum of its proper divisors (1).

492135433 is an equidigital number, since it uses as much as digits as its factorization.

492135433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 38880, while the sum is 34.

The square root of 492135433 is about 22184.1256983457. The cubic root of 492135433 is about 789.5171075489.

The spelling of 492135433 in words is "four hundred ninety-two million, one hundred thirty-five thousand, four hundred thirty-three".