Base | Representation |
---|---|
bin | 101101110111100110… |
… | …010110000111101111 |
3 | 11201010101210020010021 |
4 | 231313212112013233 |
5 | 1301331300243124 |
6 | 34343051423011 |
7 | 3362330063044 |
oct | 556746260757 |
9 | 151111706107 |
10 | 49251181039 |
11 | 1998400a305 |
12 | 9666154a67 |
13 | 484b899998 |
14 | 25530c91cb |
15 | 1433c7c7e4 |
hex | b779961ef |
49251181039 has 2 divisors, whose sum is σ = 49251181040. Its totient is φ = 49251181038.
The previous prime is 49251181033. The next prime is 49251181103. The reversal of 49251181039 is 93018115294.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49251181039 - 233 = 40661246447 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49251180986 and 49251181004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49251181033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24625590519 + 24625590520.
It is an arithmetic number, because the mean of its divisors is an integer number (24625590520).
Almost surely, 249251181039 is an apocalyptic number.
49251181039 is a deficient number, since it is larger than the sum of its proper divisors (1).
49251181039 is an equidigital number, since it uses as much as digits as its factorization.
49251181039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 43.
The spelling of 49251181039 in words is "forty-nine billion, two hundred fifty-one million, one hundred eighty-one thousand, thirty-nine".
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