Base | Representation |
---|---|
bin | 101101111000111001… |
… | …000011111101011111 |
3 | 11201011220120212101101 |
4 | 231320321003331133 |
5 | 1301402323131412 |
6 | 34345144253531 |
7 | 3363012303331 |
oct | 557071037537 |
9 | 151156525341 |
10 | 49272864607 |
11 | 1999527a50a |
12 | 96714712a7 |
13 | 485321c4b5 |
14 | 2555d31451 |
15 | 1435b12457 |
hex | b78e43f5f |
49272864607 has 2 divisors, whose sum is σ = 49272864608. Its totient is φ = 49272864606.
The previous prime is 49272864581. The next prime is 49272864611. The reversal of 49272864607 is 70646827294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49272864607 - 219 = 49272340319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49272814607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24636432303 + 24636432304.
It is an arithmetic number, because the mean of its divisors is an integer number (24636432304).
Almost surely, 249272864607 is an apocalyptic number.
49272864607 is a deficient number, since it is larger than the sum of its proper divisors (1).
49272864607 is an equidigital number, since it uses as much as digits as its factorization.
49272864607 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8128512, while the sum is 55.
The spelling of 49272864607 in words is "forty-nine billion, two hundred seventy-two million, eight hundred sixty-four thousand, six hundred seven".
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