Base | Representation |
---|---|
bin | 1110010110001111010… |
… | …00010011111100110111 |
3 | 1202010110022101101220201 |
4 | 13023013220103330313 |
5 | 31034103212131312 |
6 | 1014245251541331 |
7 | 50421251440603 |
oct | 7130750237467 |
9 | 1663408341821 |
10 | 492975505207 |
11 | 1800849035a9 |
12 | 7b6605ba847 |
13 | 37644a49893 |
14 | 19c0832c503 |
15 | cc540cb557 |
hex | 72c7a13f37 |
492975505207 has 2 divisors, whose sum is σ = 492975505208. Its totient is φ = 492975505206.
The previous prime is 492975505189. The next prime is 492975505223. The reversal of 492975505207 is 702505579294.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 492975505207 - 219 = 492974980919 is a prime.
It is a super-2 number, since 2×4929755052072 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (492975506207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246487752603 + 246487752604.
It is an arithmetic number, because the mean of its divisors is an integer number (246487752604).
Almost surely, 2492975505207 is an apocalyptic number.
492975505207 is a deficient number, since it is larger than the sum of its proper divisors (1).
492975505207 is an equidigital number, since it uses as much as digits as its factorization.
492975505207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7938000, while the sum is 55.
The spelling of 492975505207 in words is "four hundred ninety-two billion, nine hundred seventy-five million, five hundred five thousand, two hundred seven".
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