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4929921153401 is a prime number
BaseRepresentation
bin100011110111101011000…
…1100101111100101111001
3122110021222200101212100012
41013233112030233211321
51121232434303402101
614252435143351305
71016114020252046
oct107572614574571
918407880355305
104929921153401
111630849a71912
12677550752535
13299b7450152a
141308764c81cd
158838a238bbb
hex47bd632f979

4929921153401 has 2 divisors, whose sum is σ = 4929921153402. Its totient is φ = 4929921153400.

The previous prime is 4929921153341. The next prime is 4929921153463. The reversal of 4929921153401 is 1043511299294.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3214544197225 + 1715376956176 = 1792915^2 + 1309724^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4929921153401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4929921153401.

It is not a weakly prime, because it can be changed into another prime (4929921153481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2464960576700 + 2464960576701.

It is an arithmetic number, because the mean of its divisors is an integer number (2464960576701).

Almost surely, 24929921153401 is an apocalyptic number.

It is an amenable number.

4929921153401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4929921153401 is an equidigital number, since it uses as much as digits as its factorization.

4929921153401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 699840, while the sum is 50.

The spelling of 4929921153401 in words is "four trillion, nine hundred twenty-nine billion, nine hundred twenty-one million, one hundred fifty-three thousand, four hundred one".