Base | Representation |
---|---|
bin | 100011111000000011101… |
… | …1101111011011010010111 |
3 | 122110101010021202220112002 |
4 | 1013300013131323122113 |
5 | 1121241132410214342 |
6 | 14253053152145515 |
7 | 1016143345164644 |
oct | 107600735733227 |
9 | 18411107686462 |
10 | 4930747741847 |
11 | 1631133612a64 |
12 | 67774153829b |
13 | 299c76833615 |
14 | 1309141b4dcb |
15 | 883d7ab3d32 |
hex | 47c0777b697 |
4930747741847 has 2 divisors, whose sum is σ = 4930747741848. Its totient is φ = 4930747741846.
The previous prime is 4930747741831. The next prime is 4930747741861. The reversal of 4930747741847 is 7481477470394.
4930747741847 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4930747741847 - 24 = 4930747741831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4930747741867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2465373870923 + 2465373870924.
It is an arithmetic number, because the mean of its divisors is an integer number (2465373870924).
Almost surely, 24930747741847 is an apocalyptic number.
4930747741847 is a deficient number, since it is larger than the sum of its proper divisors (1).
4930747741847 is an equidigital number, since it uses as much as digits as its factorization.
4930747741847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 132765696, while the sum is 65.
The spelling of 4930747741847 in words is "four trillion, nine hundred thirty billion, seven hundred forty-seven million, seven hundred forty-one thousand, eight hundred forty-seven".
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