Base | Representation |
---|---|
bin | 111000000101110111000100… |
… | …1010001001011110100101111 |
3 | 2101200221022020102112100022222 |
4 | 1300023232021101023310233 |
5 | 1004132121400301031341 |
6 | 4505202412504025555 |
7 | 205632003441052154 |
oct | 16013561121136457 |
9 | 2350838212470288 |
10 | 493386671111471 |
11 | 133232126307675 |
12 | 47405785a622bb |
13 | 1823c218130b07 |
14 | 89ba0840c822b |
15 | 3c091bd87c44b |
hex | 1c0bb8944bd2f |
493386671111471 has 2 divisors, whose sum is σ = 493386671111472. Its totient is φ = 493386671111470.
The previous prime is 493386671111459. The next prime is 493386671111489. The reversal of 493386671111471 is 174111176683394.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-493386671111471 is a prime.
It is a super-3 number, since 3×4933866711114713 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (493386671111431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 246693335555735 + 246693335555736.
It is an arithmetic number, because the mean of its divisors is an integer number (246693335555736).
Almost surely, 2493386671111471 is an apocalyptic number.
493386671111471 is a deficient number, since it is larger than the sum of its proper divisors (1).
493386671111471 is an equidigital number, since it uses as much as digits as its factorization.
493386671111471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 18289152, while the sum is 62.
The spelling of 493386671111471 in words is "four hundred ninety-three trillion, three hundred eighty-six billion, six hundred seventy-one million, one hundred eleven thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •