Base | Representation |
---|---|
bin | 100011111001100101011… |
… | …0100101001000100110001 |
3 | 122110200120200222201211022 |
4 | 1013303022310221010301 |
5 | 1121314340431100134 |
6 | 14254354312425225 |
7 | 1016320513444355 |
oct | 107631264510461 |
9 | 18420520881738 |
10 | 4934025253169 |
11 | 1632565697801 |
12 | 6782b70a8215 |
13 | 29a37987082c |
14 | 130b455b9465 |
15 | 8852a6c352e |
hex | 47ccad29131 |
4934025253169 has 2 divisors, whose sum is σ = 4934025253170. Its totient is φ = 4934025253168.
The previous prime is 4934025253057. The next prime is 4934025253181. The reversal of 4934025253169 is 9613525204394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4109588492944 + 824436760225 = 2027212^2 + 907985^2 .
It is a cyclic number.
It is not a de Polignac number, because 4934025253169 - 212 = 4934025249073 is a prime.
It is a super-2 number, since 2×49340252531692 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4934025253169.
It is not a weakly prime, because it can be changed into another prime (4934025250169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2467012626584 + 2467012626585.
It is an arithmetic number, because the mean of its divisors is an integer number (2467012626585).
Almost surely, 24934025253169 is an apocalyptic number.
It is an amenable number.
4934025253169 is a deficient number, since it is larger than the sum of its proper divisors (1).
4934025253169 is an equidigital number, since it uses as much as digits as its factorization.
4934025253169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6998400, while the sum is 53.
The spelling of 4934025253169 in words is "four trillion, nine hundred thirty-four billion, twenty-five million, two hundred fifty-three thousand, one hundred sixty-nine".
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