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49341726720 = 21634511132
BaseRepresentation
bin101101111100111111…
…110000000000000000
311201100201011102110000
4231330333300000000
51302022440223340
634400044240000
73364506520446
oct557477600000
9151321142400
1049341726720
1119a20133650
129690540000
134864580100
142561138b96
15143bbb5d30
hexb7cff0000

49341726720 has 1020 divisors, whose sum is σ = 208965971016. Its totient is φ = 11041505280.

The previous prime is 49341726719. The next prime is 49341726743. The reversal of 49341726720 is 2762714394.

49341726720 is a `hidden beast` number, since 49 + 341 + 7 + 267 + 2 + 0 = 666.

It is a super-2 number, since 2×493417267202 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 3795517434 + ... + 3795517446.

Almost surely, 249341726720 is an apocalyptic number.

49341726720 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 49341726720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (104482985508).

49341726720 is an abundant number, since it is smaller than the sum of its proper divisors (159624244296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

49341726720 is an equidigital number, since it uses as much as digits as its factorization.

49341726720 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86 (or 34 counting only the distinct ones).

The product of its (nonzero) digits is 508032, while the sum is 45.

The spelling of 49341726720 in words is "forty-nine billion, three hundred forty-one million, seven hundred twenty-six thousand, seven hundred twenty".