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4934859557477 is a prime number
BaseRepresentation
bin100011111001111110010…
…0011010000101001100101
3122110202201211212210011212
41013303330203100221211
51121323043021314402
614255013154441205
71016350264064423
oct107637443205145
918422654783155
104934859557477
1116329536289a3
126784aa593205
1329a480674915
14130bc4314113
1588578a74952
hex47cfc8d0a65

4934859557477 has 2 divisors, whose sum is σ = 4934859557478. Its totient is φ = 4934859557476.

The previous prime is 4934859557399. The next prime is 4934859557497. The reversal of 4934859557477 is 7747559584394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4934791230721 + 68326756 = 2221439^2 + 8266^2 .

It is a cyclic number.

It is not a de Polignac number, because 4934859557477 - 220 = 4934858508901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4934859557398 and 4934859557407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4934859557497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2467429778738 + 2467429778739.

It is an arithmetic number, because the mean of its divisors is an integer number (2467429778739).

Almost surely, 24934859557477 is an apocalyptic number.

It is an amenable number.

4934859557477 is a deficient number, since it is larger than the sum of its proper divisors (1).

4934859557477 is an equidigital number, since it uses as much as digits as its factorization.

4934859557477 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5334336000, while the sum is 77.

The spelling of 4934859557477 in words is "four trillion, nine hundred thirty-four billion, eight hundred fifty-nine million, five hundred fifty-seven thousand, four hundred seventy-seven".