Base | Representation |
---|---|
bin | 101101111110010010… |
… | …100101011010110101 |
3 | 11201102020000122021221 |
4 | 231332102211122311 |
5 | 1302044020110313 |
6 | 34402141510341 |
7 | 3365162220403 |
oct | 557622453265 |
9 | 151366018257 |
10 | 49363441333 |
11 | 19a31415108 |
12 | 96978723b1 |
13 | 4868c13aab |
14 | 2563d8c473 |
15 | 143da54c8d |
hex | b7e4a56b5 |
49363441333 has 2 divisors, whose sum is σ = 49363441334. Its totient is φ = 49363441332.
The previous prime is 49363441319. The next prime is 49363441339. The reversal of 49363441333 is 33314436394.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26412100324 + 22951341009 = 162518^2 + 151497^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49363441333 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 49363441333.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49363441339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24681720666 + 24681720667.
It is an arithmetic number, because the mean of its divisors is an integer number (24681720667).
Almost surely, 249363441333 is an apocalyptic number.
It is an amenable number.
49363441333 is a deficient number, since it is larger than the sum of its proper divisors (1).
49363441333 is an equidigital number, since it uses as much as digits as its factorization.
49363441333 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 839808, while the sum is 43.
The spelling of 49363441333 in words is "forty-nine billion, three hundred sixty-three million, four hundred forty-one thousand, three hundred thirty-three".
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