Base | Representation |
---|---|
bin | 100011111011100010111… |
… | …0111010111100100111101 |
3 | 122111002110020020010202000 |
4 | 1013313011313113210331 |
5 | 1121402002141033044 |
6 | 14300332250052513 |
7 | 1016530055225055 |
oct | 107670567274475 |
9 | 18432406203660 |
10 | 4938237049149 |
11 | 1634327090428 |
12 | 67909171a139 |
13 | 29a89b3196c1 |
14 | 131024b02565 |
15 | 886c5332d69 |
hex | 47dc5dd793d |
4938237049149 has 64 divisors (see below), whose sum is σ = 7436901600000. Its totient is φ = 3238141750272.
The previous prime is 4938237049129. The next prime is 4938237049159. The reversal of 4938237049149 is 9419407328394.
4938237049149 is a `hidden beast` number, since 4 + 9 + 3 + 82 + 370 + 49 + 149 = 666.
It is not a de Polignac number, because 4938237049149 - 215 = 4938237016381 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4938237049129) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 382832302 + ... + 382845200.
It is an arithmetic number, because the mean of its divisors is an integer number (116201587500).
Almost surely, 24938237049149 is an apocalyptic number.
It is an amenable number.
4938237049149 is a deficient number, since it is larger than the sum of its proper divisors (2498664550851).
4938237049149 is a wasteful number, since it uses less digits than its factorization.
4938237049149 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13819 (or 13813 counting only the distinct ones).
The product of its (nonzero) digits is 47029248, while the sum is 63.
The spelling of 4938237049149 in words is "four trillion, nine hundred thirty-eight billion, two hundred thirty-seven million, forty-nine thousand, one hundred forty-nine".
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