Base | Representation |
---|---|
bin | 101110000000111111… |
… | …101001110011010001 |
3 | 11201112101101121200002 |
4 | 232000333221303101 |
5 | 1302142123411233 |
6 | 34410442135345 |
7 | 3366252646211 |
oct | 560077516321 |
9 | 151471347602 |
10 | 49408810193 |
11 | 19a54a92436 |
12 | 96aaab1555 |
13 | 487543a282 |
14 | 2569ddc241 |
15 | 1442a176e8 |
hex | b80fe9cd1 |
49408810193 has 2 divisors, whose sum is σ = 49408810194. Its totient is φ = 49408810192.
The previous prime is 49408810163. The next prime is 49408810201. The reversal of 49408810193 is 39101880494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47137620544 + 2271189649 = 217112^2 + 47657^2 .
It is a cyclic number.
It is not a de Polignac number, because 49408810193 - 28 = 49408809937 is a prime.
It is not a weakly prime, because it can be changed into another prime (49408810163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24704405096 + 24704405097.
It is an arithmetic number, because the mean of its divisors is an integer number (24704405097).
Almost surely, 249408810193 is an apocalyptic number.
It is an amenable number.
49408810193 is a deficient number, since it is larger than the sum of its proper divisors (1).
49408810193 is an equidigital number, since it uses as much as digits as its factorization.
49408810193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 47.
The spelling of 49408810193 in words is "forty-nine billion, four hundred eight million, eight hundred ten thousand, one hundred ninety-three".
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