Base | Representation |
---|---|
bin | 10110011110010110000110… |
… | …00011111111101111110001 |
3 | 20110222121200001110021210011 |
4 | 23033023003003333233301 |
5 | 22434204022033444213 |
6 | 253035434222334521 |
7 | 13260363400310566 |
oct | 1317130303775761 |
9 | 213877601407704 |
10 | 49421166312433 |
11 | 14824442a81393 |
12 | 56621a072a441 |
13 | 217651bc9b2c6 |
14 | c2bdd64ca86d |
15 | 5aa85814203d |
hex | 2cf2c30ffbf1 |
49421166312433 has 2 divisors, whose sum is σ = 49421166312434. Its totient is φ = 49421166312432.
The previous prime is 49421166312389. The next prime is 49421166312491. The reversal of 49421166312433 is 33421366112494.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25283921569344 + 24137244743089 = 5028312^2 + 4912967^2 .
It is a cyclic number.
It is not a de Polignac number, because 49421166312433 - 245 = 14236794223601 is a prime.
It is a super-2 number, since 2×494211663124332 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49421166312233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24710583156216 + 24710583156217.
It is an arithmetic number, because the mean of its divisors is an integer number (24710583156217).
Almost surely, 249421166312433 is an apocalyptic number.
It is an amenable number.
49421166312433 is a deficient number, since it is larger than the sum of its proper divisors (1).
49421166312433 is an equidigital number, since it uses as much as digits as its factorization.
49421166312433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2239488, while the sum is 49.
The spelling of 49421166312433 in words is "forty-nine trillion, four hundred twenty-one billion, one hundred sixty-six million, three hundred twelve thousand, four hundred thirty-three".
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