Base | Representation |
---|---|
bin | 10110011110100001111111… |
… | …01100110101001001100101 |
3 | 20111000020011002221001210212 |
4 | 23033100333230311021211 |
5 | 22434310111400442023 |
6 | 253042412025425205 |
7 | 13261010552644313 |
oct | 1317207754651145 |
9 | 214006132831725 |
10 | 49427552359013 |
11 | 1482711a807734 |
12 | 566348333b205 |
13 | 2176cc90314aa |
14 | c2c4406ab0b3 |
15 | 5aaacdad3e78 |
hex | 2cf43fb35265 |
49427552359013 has 2 divisors, whose sum is σ = 49427552359014. Its totient is φ = 49427552359012.
The previous prime is 49427552358967. The next prime is 49427552359033. The reversal of 49427552359013 is 31095325572494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43678788474049 + 5748763884964 = 6608993^2 + 2397658^2 .
It is a cyclic number.
It is not a de Polignac number, because 49427552359013 - 26 = 49427552358949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49427552359033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24713776179506 + 24713776179507.
It is an arithmetic number, because the mean of its divisors is an integer number (24713776179507).
Almost surely, 249427552359013 is an apocalyptic number.
It is an amenable number.
49427552359013 is a deficient number, since it is larger than the sum of its proper divisors (1).
49427552359013 is an equidigital number, since it uses as much as digits as its factorization.
49427552359013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824000, while the sum is 59.
The spelling of 49427552359013 in words is "forty-nine trillion, four hundred twenty-seven billion, five hundred fifty-two million, three hundred fifty-nine thousand, thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •