Base | Representation |
---|---|
bin | 1011110010010… |
… | …0001001010111 |
3 | 10110000100202111 |
4 | 2330210021113 |
5 | 100123244002 |
6 | 4523251451 |
7 | 1140105034 |
oct | 274441127 |
9 | 113010674 |
10 | 49431127 |
11 | 259a2379 |
12 | 14679b87 |
13 | a3194b5 |
14 | 67ca38b |
15 | 45163d7 |
hex | 2f24257 |
49431127 has 2 divisors, whose sum is σ = 49431128. Its totient is φ = 49431126.
The previous prime is 49431119. The next prime is 49431131. The reversal of 49431127 is 72113494.
49431127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49431127 - 23 = 49431119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49431227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24715563 + 24715564.
It is an arithmetic number, because the mean of its divisors is an integer number (24715564).
Almost surely, 249431127 is an apocalyptic number.
49431127 is a deficient number, since it is larger than the sum of its proper divisors (1).
49431127 is an equidigital number, since it uses as much as digits as its factorization.
49431127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6048, while the sum is 31.
The square root of 49431127 is about 7030.7273450191. The cubic root of 49431127 is about 367.0006533558. Note that the first 3 decimals are identical.
The spelling of 49431127 in words is "forty-nine million, four hundred thirty-one thousand, one hundred twenty-seven".
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