4943734534121 has 2 divisors, whose sum is σ = 4943734534122. Its totient is φ = 4943734534120.

The previous prime is 4943734534099. The next prime is 4943734534171. The reversal of 4943734534121 is 1214354373494.

It is an a-pointer prime, because the next prime (4943734534171) can be obtained adding 4943734534121 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4936950705625 + 6783828496 = 2221925^2 + 82364^2 .

It is a cyclic number.

It is not a de Polignac number, because 4943734534121 - 2¹⁰ = 4943734533097 is a prime.

It is a super-2 number, since 2×4943734534121² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4943734534121.

It is not a weakly prime, because it can be changed into another prime (4943734534171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2471867267060 + 2471867267061.

It is an arithmetic number, because the mean of its divisors is an integer number (2471867267061).

Almost surely, 2^{4943734534121} is an apocalyptic number.

It is an amenable number.

4943734534121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4943734534121 is an equidigital number, since it uses as much as digits as its factorization.

4943734534121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4354560, while the sum is 50.

The spelling of 4943734534121 in words is "four trillion, nine hundred forty-three billion, seven hundred thirty-four million, five hundred thirty-four thousand, one hundred twenty-one".