Base | Representation |
---|---|
bin | 111000001110001111111101… |
… | …1100110011101000000000111 |
3 | 2101212000112020211220010000021 |
4 | 1300130133323212131000013 |
5 | 1004310014140433243212 |
6 | 4511444212520000011 |
7 | 206111211212264203 |
oct | 16034377346350007 |
9 | 2355015224803007 |
10 | 494539640524807 |
11 | 1336370a14aa919 |
12 | 47571119000007 |
13 | 182c3b70c112c7 |
14 | 8a19bbc405b03 |
15 | 3c2919e724307 |
hex | 1c1c7fb99d007 |
494539640524807 has 2 divisors, whose sum is σ = 494539640524808. Its totient is φ = 494539640524806.
The previous prime is 494539640524789. The next prime is 494539640524829. The reversal of 494539640524807 is 708425046935494.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-494539640524807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (494539640525807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247269820262403 + 247269820262404.
It is an arithmetic number, because the mean of its divisors is an integer number (247269820262404).
Almost surely, 2494539640524807 is an apocalyptic number.
494539640524807 is a deficient number, since it is larger than the sum of its proper divisors (1).
494539640524807 is an equidigital number, since it uses as much as digits as its factorization.
494539640524807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1045094400, while the sum is 70.
The spelling of 494539640524807 in words is "four hundred ninety-four trillion, five hundred thirty-nine billion, six hundred forty million, five hundred twenty-four thousand, eight hundred seven".
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