Base | Representation |
---|---|
bin | 101110000011110111… |
… | …001010001100001101 |
3 | 11201122201220121100111 |
4 | 232003313022030031 |
5 | 1302241432241323 |
6 | 34415321200021 |
7 | 3400405562116 |
oct | 560367121415 |
9 | 151581817314 |
10 | 49456915213 |
11 | 19a7a159452 |
12 | 9703030011 |
13 | 48823b0c94 |
14 | 257256120d |
15 | 1446d6ac0d |
hex | b83dca30d |
49456915213 has 2 divisors, whose sum is σ = 49456915214. Its totient is φ = 49456915212.
The previous prime is 49456915187. The next prime is 49456915223. The reversal of 49456915213 is 31251965494.
49456915213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49318193929 + 138721284 = 222077^2 + 11778^2 .
It is a cyclic number.
It is not a de Polignac number, because 49456915213 - 229 = 48920044301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49456915223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24728457606 + 24728457607.
It is an arithmetic number, because the mean of its divisors is an integer number (24728457607).
Almost surely, 249456915213 is an apocalyptic number.
It is an amenable number.
49456915213 is a deficient number, since it is larger than the sum of its proper divisors (1).
49456915213 is an equidigital number, since it uses as much as digits as its factorization.
49456915213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1166400, while the sum is 49.
The spelling of 49456915213 in words is "forty-nine billion, four hundred fifty-six million, nine hundred fifteen thousand, two hundred thirteen".
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