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49456915213 is a prime number
BaseRepresentation
bin101110000011110111…
…001010001100001101
311201122201220121100111
4232003313022030031
51302241432241323
634415321200021
73400405562116
oct560367121415
9151581817314
1049456915213
1119a7a159452
129703030011
1348823b0c94
14257256120d
151446d6ac0d
hexb83dca30d

49456915213 has 2 divisors, whose sum is σ = 49456915214. Its totient is φ = 49456915212.

The previous prime is 49456915187. The next prime is 49456915223. The reversal of 49456915213 is 31251965494.

49456915213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49318193929 + 138721284 = 222077^2 + 11778^2 .

It is a cyclic number.

It is not a de Polignac number, because 49456915213 - 229 = 48920044301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49456915223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24728457606 + 24728457607.

It is an arithmetic number, because the mean of its divisors is an integer number (24728457607).

Almost surely, 249456915213 is an apocalyptic number.

It is an amenable number.

49456915213 is a deficient number, since it is larger than the sum of its proper divisors (1).

49456915213 is an equidigital number, since it uses as much as digits as its factorization.

49456915213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1166400, while the sum is 49.

The spelling of 49456915213 in words is "forty-nine billion, four hundred fifty-six million, nine hundred fifteen thousand, two hundred thirteen".