Base | Representation |
---|---|
bin | 10110011111111001000011… |
… | …01011011000001011101111 |
3 | 20111011200210120020222200101 |
4 | 23033330201223120023233 |
5 | 22441041323041130444 |
6 | 253120102050211531 |
7 | 13264254052261156 |
oct | 1317744153301357 |
9 | 214150716228611 |
10 | 49474293301999 |
11 | 14844a2585aa35 |
12 | 5670548883ba7 |
13 | 217b5378259c7 |
14 | c307d623c59d |
15 | 5abe172b23d4 |
hex | 2cff21ad82ef |
49474293301999 has 2 divisors, whose sum is σ = 49474293302000. Its totient is φ = 49474293301998.
The previous prime is 49474293301987. The next prime is 49474293302023. The reversal of 49474293301999 is 99910339247494.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49474293301999 - 25 = 49474293301967 is a prime.
It is a super-2 number, since 2×494742933019992 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49474293301919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24737146650999 + 24737146651000.
It is an arithmetic number, because the mean of its divisors is an integer number (24737146651000).
Almost surely, 249474293301999 is an apocalyptic number.
49474293301999 is a deficient number, since it is larger than the sum of its proper divisors (1).
49474293301999 is an equidigital number, since it uses as much as digits as its factorization.
49474293301999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 476171136, while the sum is 73.
It can be divided in two parts, 4947429 and 3301999, that added together give a palindrome (8249428).
The spelling of 49474293301999 in words is "forty-nine trillion, four hundred seventy-four billion, two hundred ninety-three million, three hundred one thousand, nine hundred ninety-nine".
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