Base | Representation |
---|---|
bin | 1110011001101000000… |
… | …01011001111010110101 |
3 | 1202022011001020122210001 |
4 | 13030310001121322311 |
5 | 31101314232210311 |
6 | 1015145533031301 |
7 | 50514312540535 |
oct | 7146401317265 |
9 | 1668131218701 |
10 | 494794022581 |
11 | 180928365621 |
12 | 7ba89625531 |
13 | 37874721271 |
14 | 19d3ba654c5 |
15 | cd0da914c1 |
hex | 7334059eb5 |
494794022581 has 2 divisors, whose sum is σ = 494794022582. Its totient is φ = 494794022580.
The previous prime is 494794022549. The next prime is 494794022587. The reversal of 494794022581 is 185220497494.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 353091466225 + 141702556356 = 594215^2 + 376434^2 .
It is a cyclic number.
It is not a de Polignac number, because 494794022581 - 25 = 494794022549 is a prime.
It is a super-2 number, since 2×4947940225812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (494794022587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247397011290 + 247397011291.
It is an arithmetic number, because the mean of its divisors is an integer number (247397011291).
Almost surely, 2494794022581 is an apocalyptic number.
It is an amenable number.
494794022581 is a deficient number, since it is larger than the sum of its proper divisors (1).
494794022581 is an equidigital number, since it uses as much as digits as its factorization.
494794022581 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 494794022581 in words is "four hundred ninety-four billion, seven hundred ninety-four million, twenty-two thousand, five hundred eighty-one".
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