Search a number
-
+
495115117 = 770730731
BaseRepresentation
bin11101100000101…
…101101101101101
31021111122110020221
4131200231231231
52003222140432
6121044011341
715161260210
oct3540555555
91244573227
10495115117
11234530352
12119990b51
137b764833
1449a83777
152d700b97
hex1d82db6d

495115117 has 4 divisors (see below), whose sum is σ = 565845856. Its totient is φ = 424384380.

The previous prime is 495115111. The next prime is 495115133. The reversal of 495115117 is 711511594.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 711511594 = 2355755797.

It is not a de Polignac number, because 495115117 - 23 = 495115109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (495115111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35365359 + ... + 35365372.

It is an arithmetic number, because the mean of its divisors is an integer number (141461464).

Almost surely, 2495115117 is an apocalyptic number.

It is an amenable number.

495115117 is a deficient number, since it is larger than the sum of its proper divisors (70730739).

495115117 is an equidigital number, since it uses as much as digits as its factorization.

495115117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70730738.

The product of its digits is 6300, while the sum is 34.

The square root of 495115117 is about 22251.1823730785. The cubic root of 495115117 is about 791.1073063720.

The spelling of 495115117 in words is "four hundred ninety-five million, one hundred fifteen thousand, one hundred seventeen".

Divisors: 1 7 70730731 495115117