Base | Representation |
---|---|
bin | 1110011010100101111… |
… | …00011001010101001011 |
3 | 1202100111012102102221002 |
4 | 13031102330121111023 |
5 | 31103400034200042 |
6 | 1015313224205215 |
7 | 50533212234401 |
oct | 7152274312513 |
9 | 1670435372832 |
10 | 495312803147 |
11 | 18107418a098 |
12 | 7bbb330980b |
13 | 37928050706 |
14 | 19d8a909471 |
15 | cd3e3b9132 |
hex | 7352f1954b |
495312803147 has 2 divisors, whose sum is σ = 495312803148. Its totient is φ = 495312803146.
The previous prime is 495312803087. The next prime is 495312803299. The reversal of 495312803147 is 741308213594.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 495312803147 - 222 = 495308608843 is a prime.
It is a super-2 number, since 2×4953128031472 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (495312823147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247656401573 + 247656401574.
It is an arithmetic number, because the mean of its divisors is an integer number (247656401574).
Almost surely, 2495312803147 is an apocalyptic number.
495312803147 is a deficient number, since it is larger than the sum of its proper divisors (1).
495312803147 is an equidigital number, since it uses as much as digits as its factorization.
495312803147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 495312803147 in words is "four hundred ninety-five billion, three hundred twelve million, eight hundred three thousand, one hundred forty-seven".
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