4953312000053 has 2 divisors, whose sum is σ = 4953312000054. Its totient is φ = 4953312000052.

The previous prime is 4953311999971. The next prime is 4953312000073. The reversal of 4953312000053 is 3500002133594.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3091664605969 + 1861647394084 = 1758313^2 + 1364422^2 .

It is a cyclic number.

It is not a de Polignac number, because 4953312000053 - 2¹⁶ = 4953311934517 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4953311999977 and 4953312000022.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4953312000073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2476656000026 + 2476656000027.

It is an arithmetic number, because the mean of its divisors is an integer number (2476656000027).

Almost surely, 2^{4953312000053} is an apocalyptic number.

It is an amenable number.

4953312000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

4953312000053 is an equidigital number, since it uses as much as digits as its factorization.

4953312000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 35.

The spelling of 4953312000053 in words is "four trillion, nine hundred fifty-three billion, three hundred twelve million, fifty-three", and thus it is an aban number.