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49555469343749 is a prime number
BaseRepresentation
bin10110100010010000010000…
…01001011001110000000101
320111110110022212022011200012
423101020020021121300011
522443404100122444444
6253221245054400005
713303156504245005
oct1321101011316005
9214413285264605
1049555469343749
11148763a1599646
125684222500005
1321860a34b3cc5
14c346d726c005
155ae0b8b37b9e
hex2d1208259c05

49555469343749 has 2 divisors, whose sum is σ = 49555469343750. Its totient is φ = 49555469343748.

The previous prime is 49555469343719. The next prime is 49555469343773. The reversal of 49555469343749 is 94734396455594.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43447305382849 + 6108163960900 = 6591457^2 + 2471470^2 .

It is a cyclic number.

It is not a de Polignac number, because 49555469343749 - 236 = 49486749867013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 49555469343749.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49555469343719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24777734671874 + 24777734671875.

It is an arithmetic number, because the mean of its divisors is an integer number (24777734671875).

Almost surely, 249555469343749 is an apocalyptic number.

It is an amenable number.

49555469343749 is a deficient number, since it is larger than the sum of its proper divisors (1).

49555469343749 is an equidigital number, since it uses as much as digits as its factorization.

49555469343749 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8817984000, while the sum is 77.

The spelling of 49555469343749 in words is "forty-nine trillion, five hundred fifty-five billion, four hundred sixty-nine million, three hundred forty-three thousand, seven hundred forty-nine".