Base | Representation |
---|---|
bin | 11101100010011… |
… | …110011110001101 |
3 | 1021112111220210201 |
4 | 131202132132031 |
5 | 2003331430343 |
6 | 121101533501 |
7 | 15165222553 |
oct | 3542363615 |
9 | 1245456721 |
10 | 495576973 |
11 | 234816351 |
12 | 119b74291 |
13 | 7b896b18 |
14 | 49b63bd3 |
15 | 2d79294d |
hex | 1d89e78d |
495576973 has 2 divisors, whose sum is σ = 495576974. Its totient is φ = 495576972.
The previous prime is 495576967. The next prime is 495576997. The reversal of 495576973 is 379675594.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 327537604 + 168039369 = 18098^2 + 12963^2 .
It is a cyclic number.
It is not a de Polignac number, because 495576973 - 213 = 495568781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (495576923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247788486 + 247788487.
It is an arithmetic number, because the mean of its divisors is an integer number (247788487).
Almost surely, 2495576973 is an apocalyptic number.
It is an amenable number.
495576973 is a deficient number, since it is larger than the sum of its proper divisors (1).
495576973 is an equidigital number, since it uses as much as digits as its factorization.
495576973 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7144200, while the sum is 55.
The square root of 495576973 is about 22261.5581889498. The cubic root of 495576973 is about 791.3532182763.
The spelling of 495576973 in words is "four hundred ninety-five million, five hundred seventy-six thousand, nine hundred seventy-three".
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