Search a number
-
+
496115553103 is a prime number
BaseRepresentation
bin1110011100000101100…
…10101001001101001111
31202102120010221100211221
413032002302221031033
531112021040144403
61015525022024211
750562130423312
oct7160262511517
91672503840757
10496115553103
11181446329005
1280198118067
1337a254571a1
141a02538c979
15cd89ad5dbd
hex7382ca934f

496115553103 has 2 divisors, whose sum is σ = 496115553104. Its totient is φ = 496115553102.

The previous prime is 496115553061. The next prime is 496115553113. The reversal of 496115553103 is 301355511694.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-496115553103 is a prime.

It is a super-2 number, since 2×4961155531032 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 496115553103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (496115553113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248057776551 + 248057776552.

It is an arithmetic number, because the mean of its divisors is an integer number (248057776552).

Almost surely, 2496115553103 is an apocalyptic number.

496115553103 is a deficient number, since it is larger than the sum of its proper divisors (1).

496115553103 is an equidigital number, since it uses as much as digits as its factorization.

496115553103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 496115553103 in words is "four hundred ninety-six billion, one hundred fifteen million, five hundred fifty-three thousand, one hundred three".