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49612144447 is a prime number
BaseRepresentation
bin101110001101000111…
…010011111100111111
311202001120000001211101
4232031013103330333
51303101202110242
634442544233531
73404302161355
oct561507237477
9152046001741
1049612144447
111a049842478
12974700b8a7
1348a85c10b8
14258900b7d5
1514557ce9b7
hexb8d1d3f3f

49612144447 has 2 divisors, whose sum is σ = 49612144448. Its totient is φ = 49612144446.

The previous prime is 49612144397. The next prime is 49612144459. The reversal of 49612144447 is 74444121694.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-49612144447 is a prime.

It is a super-2 number, since 2×496121444472 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 49612144397 and 49612144406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49612144147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24806072223 + 24806072224.

It is an arithmetic number, because the mean of its divisors is an integer number (24806072224).

Almost surely, 249612144447 is an apocalyptic number.

49612144447 is a deficient number, since it is larger than the sum of its proper divisors (1).

49612144447 is an equidigital number, since it uses as much as digits as its factorization.

49612144447 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 774144, while the sum is 46.

The spelling of 49612144447 in words is "forty-nine billion, six hundred twelve million, one hundred forty-four thousand, four hundred forty-seven".