Base | Representation |
---|---|
bin | 101110001101000111… |
… | …010011111100111111 |
3 | 11202001120000001211101 |
4 | 232031013103330333 |
5 | 1303101202110242 |
6 | 34442544233531 |
7 | 3404302161355 |
oct | 561507237477 |
9 | 152046001741 |
10 | 49612144447 |
11 | 1a049842478 |
12 | 974700b8a7 |
13 | 48a85c10b8 |
14 | 258900b7d5 |
15 | 14557ce9b7 |
hex | b8d1d3f3f |
49612144447 has 2 divisors, whose sum is σ = 49612144448. Its totient is φ = 49612144446.
The previous prime is 49612144397. The next prime is 49612144459. The reversal of 49612144447 is 74444121694.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-49612144447 is a prime.
It is a super-2 number, since 2×496121444472 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 49612144397 and 49612144406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49612144147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24806072223 + 24806072224.
It is an arithmetic number, because the mean of its divisors is an integer number (24806072224).
Almost surely, 249612144447 is an apocalyptic number.
49612144447 is a deficient number, since it is larger than the sum of its proper divisors (1).
49612144447 is an equidigital number, since it uses as much as digits as its factorization.
49612144447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 774144, while the sum is 46.
The spelling of 49612144447 in words is "forty-nine billion, six hundred twelve million, one hundred forty-four thousand, four hundred forty-seven".
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