49613147 has 2 divisors, whose sum is σ = 49613148. Its totient is φ = 49613146.

The previous prime is 49613129. The next prime is 49613149. The reversal of 49613147 is 74131694.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 49613147 - 2²⁴ = 32835931 is a prime.

It is a super-2 number, since 2×49613147² = 4922928710487218, which contains 22 as substring.

Together with 49613149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (49613149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24806573 + 24806574.

It is an arithmetic number, because the mean of its divisors is an integer number (24806574).

Almost surely, 2^49613147 is an apocalyptic number.

49613147 is a deficient number, since it is larger than the sum of its proper divisors (1).

49613147 is an equidigital number, since it uses as much as digits as its factorization.

49613147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18144, while the sum is 35.

The square root of 49613147 is about 7043.6600571010. The cubic root of 49613147 is about 367.4505698091.

The spelling of 49613147 in words is "forty-nine million, six hundred thirteen thousand, one hundred forty-seven".