Base | Representation |
---|---|
bin | 10110100101101101000110… |
… | …01101000001110000000101 |
3 | 20111212210100220021110010212 |
4 | 23102312203031001300011 |
5 | 23002324410412120433 |
6 | 253351534145325205 |
7 | 13314554614543613 |
oct | 1322664315016005 |
9 | 214783326243125 |
10 | 49674034879493 |
11 | 14911704765512 |
12 | 56a31b1936805 |
13 | 219431a44394b |
14 | c3a343c906b3 |
15 | 5b2207bdbd48 |
hex | 2d2da3341c05 |
49674034879493 has 2 divisors, whose sum is σ = 49674034879494. Its totient is φ = 49674034879492.
The previous prime is 49674034879471. The next prime is 49674034879523. The reversal of 49674034879493 is 39497843047694.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38449511388289 + 11224523491204 = 6200767^2 + 3350302^2 .
It is a cyclic number.
It is not a de Polignac number, because 49674034879493 - 216 = 49674034813957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49674034879093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24837017439746 + 24837017439747.
It is an arithmetic number, because the mean of its divisors is an integer number (24837017439747).
Almost surely, 249674034879493 is an apocalyptic number.
It is an amenable number.
49674034879493 is a deficient number, since it is larger than the sum of its proper divisors (1).
49674034879493 is an equidigital number, since it uses as much as digits as its factorization.
49674034879493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3950456832, while the sum is 77.
The spelling of 49674034879493 in words is "forty-nine trillion, six hundred seventy-four billion, thirty-four million, eight hundred seventy-nine thousand, four hundred ninety-three".
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