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4970344403 is a prime number
BaseRepresentation
bin1001010000100000…
…10110111111010011
3110211101120122201202
410220100112333103
540134402010103
62141111421415
7234112142003
oct45020267723
913741518652
104970344403
1121206a2352
12b6868486b
136129775bb
14352182003
151e1549988
hex128416fd3

4970344403 has 2 divisors, whose sum is σ = 4970344404. Its totient is φ = 4970344402.

The previous prime is 4970344369. The next prime is 4970344411. The reversal of 4970344403 is 3044430794.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4970344403 - 214 = 4970328019 is a prime.

It is not a weakly prime, because it can be changed into another prime (4970344453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485172201 + 2485172202.

It is an arithmetic number, because the mean of its divisors is an integer number (2485172202).

Almost surely, 24970344403 is an apocalyptic number.

4970344403 is a deficient number, since it is larger than the sum of its proper divisors (1).

4970344403 is an equidigital number, since it uses as much as digits as its factorization.

4970344403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 38.

The square root of 4970344403 is about 70500.6695216436. The cubic root of 4970344403 is about 1706.5885503025.

The spelling of 4970344403 in words is "four billion, nine hundred seventy million, three hundred forty-four thousand, four hundred three".