Base | Representation |
---|---|
bin | 11101101000010… |
… | …110100010101001 |
3 | 1021122102011210211 |
4 | 131220112202221 |
5 | 2004230223403 |
6 | 121154541121 |
7 | 15214266505 |
oct | 3550264251 |
9 | 1248364724 |
10 | 497117353 |
11 | 235678697 |
12 | 11a5977a1 |
13 | 7bcb5ca5 |
14 | 4a045305 |
15 | 2d99906d |
hex | 1da168a9 |
497117353 has 2 divisors, whose sum is σ = 497117354. Its totient is φ = 497117352.
The previous prime is 497117339. The next prime is 497117393. The reversal of 497117353 is 353711794.
It is an a-pointer prime, because the next prime (497117393) can be obtained adding 497117353 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 496041984 + 1075369 = 22272^2 + 1037^2 .
It is a cyclic number.
It is not a de Polignac number, because 497117353 - 25 = 497117321 is a prime.
It is not a weakly prime, because it can be changed into another prime (497117393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248558676 + 248558677.
It is an arithmetic number, because the mean of its divisors is an integer number (248558677).
Almost surely, 2497117353 is an apocalyptic number.
It is an amenable number.
497117353 is a deficient number, since it is larger than the sum of its proper divisors (1).
497117353 is an equidigital number, since it uses as much as digits as its factorization.
497117353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 79380, while the sum is 40.
The square root of 497117353 is about 22296.1286549930. The cubic root of 497117353 is about 792.1722796539.
The spelling of 497117353 in words is "four hundred ninety-seven million, one hundred seventeen thousand, three hundred fifty-three".
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