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497127756902879 is a prime number
BaseRepresentation
bin111000100001000101001001…
…1010110111011000111011111
32102012011221122010110110211002
41301002022103112323013133
51010124420121231343004
64521145201100020515
7206466203151441224
oct16102122326730737
92365157563413732
10497127756902879
11134444774750153
124790a833b3173b
1318450c3c0c780b
148aa917cb7394b
153c7167913b61e
hex1c422935bb1df

497127756902879 has 2 divisors, whose sum is σ = 497127756902880. Its totient is φ = 497127756902878.

The previous prime is 497127756902837. The next prime is 497127756902891. The reversal of 497127756902879 is 978209657721794.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 497127756902879 - 212 = 497127756898783 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 497127756902797 and 497127756902806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (497127756907879) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248563878451439 + 248563878451440.

It is an arithmetic number, because the mean of its divisors is an integer number (248563878451440).

Almost surely, 2497127756902879 is an apocalyptic number.

497127756902879 is a deficient number, since it is larger than the sum of its proper divisors (1).

497127756902879 is an equidigital number, since it uses as much as digits as its factorization.

497127756902879 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6721263360, while the sum is 83.

The spelling of 497127756902879 in words is "four hundred ninety-seven trillion, one hundred twenty-seven billion, seven hundred fifty-six million, nine hundred two thousand, eight hundred seventy-nine".