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4971313483 is a prime number
BaseRepresentation
bin1001010000101000…
…00011100101001011
3110211110101220001121
410220110003211023
540140124012413
62141144300111
7234123316213
oct45024034513
913743356047
104971313483
1121211a4444
12b68a71637
13612c26716
14352355243
151e168bb8d
hex12850394b

4971313483 has 2 divisors, whose sum is σ = 4971313484. Its totient is φ = 4971313482.

The previous prime is 4971313447. The next prime is 4971313511. The reversal of 4971313483 is 3843131794.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4971313483 - 225 = 4937759051 is a prime.

It is not a weakly prime, because it can be changed into another prime (4971313283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485656741 + 2485656742.

It is an arithmetic number, because the mean of its divisors is an integer number (2485656742).

Almost surely, 24971313483 is an apocalyptic number.

4971313483 is a deficient number, since it is larger than the sum of its proper divisors (1).

4971313483 is an equidigital number, since it uses as much as digits as its factorization.

4971313483 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 217728, while the sum is 43.

The square root of 4971313483 is about 70507.5420292042. The cubic root of 4971313483 is about 1706.6994556528.

The spelling of 4971313483 in words is "four billion, nine hundred seventy-one million, three hundred thirteen thousand, four hundred eighty-three".